8m^2-57+7=0

Solution for 8m^2-57+7=0 equation:

8m^2-57+7=0

We add all the numbers together, and all the variables

8m^2-50=0

a = 8; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·8·(-50)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*8}=\frac{-40}{16}
=-2+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*8}=\frac{40}{16}
=2+1/2
$